As presented in the chapter:
| def HasTwoAndLater(astr): |
| for i in range(len(astr)-1): |
| if astr[i]==astr[i+1]: |
| break |
| # now, out of the loop; astr[i] is the double letter |
| # but "return" instead of break would be incorrect |
| for j in range(i+2,len(astr)): |
| if astr[j]==astr[i]: |
| return True |
| # in this second loop, early return is OK |
| return False |
| print HasTwoAndLater("too far") |
| print HasTwoAndLater("see me") |