>>> a = b = 5
>>> a == b
>>> a is b

hint answer

the 'is' operator compares the origin of two things

True
True

>>> a = b = [0]
>>> a == b
>>> a is b

hint answer

the 'is' operator compares the origin of two things

True
True

>>> a = [0]
>>> b = [5-5]
>>> a == b
>>> a is b

hint answer

the 'is' operator compares the origin of two things

True
False

>>> a = 5
>>> b = 5
>>> a == b
>>> a is b

hint answer

this might see like Python is wrong

True
True

>>> a = "five"
>>> b = "five"
>>> a == b
>>> a is b

hint answer

this might see like Python is wrong

True
True

>>> a = {5:"five"}
>>> b = {5:"five"}
>>> a == b
>>> a is b

hint answer

the 'is' operator compares the origin of two mutable variables

True
False

>>> a = b = {5:"five"}
>>> a == b
>>> a is b

hint answer

the 'is' operator compares the origin of two mutable variables

True
True

>>> a = {5:"five"}
>>> b = {5:"five"}
>>> b[2] = "two"
>>> a
>>> b
>>> a == b

hint answer

assignment can add an entry to a dictionary

{5:'five'}
{2:'two', 5:'five'}
False

>>> a = b = {5:"five"}
>>> b[2] = "two"
>>> a
>>> b
>>> a == b

hint answer

if 'a is b' is True, then assignment to one assigns to the other

{2:'two', 5:'five'}
{2:'two', 5:'five'}
True

>>> a = b = [15,2,0]
>>> Evt = [a,100]
>>> Fvt = [b,500]
>>> Evt[0].append(-1)
>>> Fvt

hint answer

surprise, but the same principle (about 'is') is at work

[[15,2,0,-1], 500]

>>> a = [15,2,0]
>>> b = a
>>> a == b
>>> a is b
>>> not a is b

hint answer

assigning from an existing variable shares origin

True
True
False

>>> a = [15,2,0]
>>> b = a[:]
>>> a == b
>>> a is b

hint answer

recall that the slice '[:]' is a copy of the entire list

True
False
The '[:]' produces a copy, but it does not have the same origin